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	<title>Austin Matzko&#039;s Blog &#187; McDonald&#8217;s</title>
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		<title>McDonald&#8217;s Spaced Out</title>
		<link>http://austinmatzko.com/2008/04/16/mcdonalds-and-astrophysics/</link>
		<comments>http://austinmatzko.com/2008/04/16/mcdonalds-and-astrophysics/#comments</comments>
		<pubDate>Wed, 16 Apr 2008 16:31:42 +0000</pubDate>
		<dc:creator>filosofo</dc:creator>
				<category><![CDATA[Education]]></category>
		<category><![CDATA[Science]]></category>
		<category><![CDATA[McDonald's]]></category>

		<guid isPermaLink="false">http://www.ilfilosofo.com/?p=445</guid>
		<description><![CDATA[This is McDonald&#8217;s idea of making their Happy Meals educational. (That I took this photograph may also be proof of bad parenting on our part, but let&#8217;s overlook that.) I think what they mean is that you can jump six times as high on the Moon. In case you were wondering, that&#8217;s because the surface [...]]]></description>
			<content:encoded><![CDATA[<p>This is McDonald&#8217;s idea of making their Happy Meals educational.  (That I took this photograph may also be proof of bad parenting on our part, but let&#8217;s overlook that.)</p>
<p><img src="http://www.ilfilosofo.com/wp-content/uploads/space_jump.jpg" alt="You can jump 6 times higher in space!" title="You can jump 6 times higher in space!" class="alignnone size-full wp-image-446" /></p>
<p>I think what they mean is that you can jump six times as high on the Moon.  </p>
<p>In case you were wondering, that&#8217;s because the <a href="http://en.wikipedia.org/wiki/Surface_gravity">surface gravity</a> of the Moon is 1/6 that of the Earth&#8217;s.  It&#8217;s <em>not</em> because the moon has 1/6 the mass or the diameter of the Earth, as you might suspect.  In fact, as you can see <a href="http://nssdc.gsfc.nasa.gov/planetary/factsheet/moonfact.html">here</a>, the mass of the Moon is 1.23% of the Earth&#8217;s, and its radius is 27.25%.</p>
<p>Surface gravity can be expressed like so:</p>
<p><code>( Surface gravity of the Moon/Surface gravity of the Earth ) = ( Mass of Moon/Mass of the Earth ) / ( Radius of Moon / Radius of Earth ) <sup>2</sup></code></p>
<p>Plug in the numbers, and you get the following:</p>
<p><code>( Surface gravity of the Moon/Surface gravity of the Earth ) = ( 0.07349 x 10<sup>24</sup> kg/5.9736 x 10<sup>24</sup> kg ) / ( 1738.1 km / 6378.1 km ) <sup>2</sup></code></p>
<p>Which ends up as <code>Surface gravity of the Moon/Surface gravity of the Earth = 0.1656 ~ 1/6</code></p>
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